6x+28=4x^2

Solution for 6x+28=4x^2 equation:

6x+28=4x^2

We move all terms to the left:

6x+28-(4x^2)=0

determiningTheFunctionDomain
-4x^2+6x+28=0

a = -4; b = 6; c = +28;
Δ = b2-4ac
Δ = 62-4·(-4)·28
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-22}{2*-4}=\frac{-28}{-8}
=3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+22}{2*-4}=\frac{16}{-8}
=-2
$